Abstract
We say a finite poset P is a tree poset if its Hasse diagram is a tree. Let k be the length of the largest chain contained in P. We show that when P is a fixed tree poset, the number of P-free set systems in 2[n] is 2(1+o(1))(k-1)n⌊n/2⌋. The proof uses a generalization of a theorem by Boris Bukh together with a variation of the multiphase graph container algorithm.
Original language | English (US) |
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Journal | Order |
Early online date | Jan 30 2025 |
DOIs | |
State | E-pub ahead of print - Jan 30 2025 |
Keywords
- Containers
- Forbidden subposet
- Set system
- Supersaturation
- Tree poset
ASJC Scopus subject areas
- Algebra and Number Theory
- Geometry and Topology
- Discrete Mathematics and Combinatorics
- Computational Theory and Mathematics